Find the function satisfying the differential equation f′(t)−f(t)=3t f′(t)−f(t)=3t and the condition f(1)=−1f(1)=−1.

explanation:

infrared radiation has wavelength in the range between 700 nm and 1 mm. lets' convert these values into scientific notation, keeping in mind that:

let's start from the lower value, we have:

(we moved the dot two places to the left, so we increased the exponent by 2 units, from -9 to -7)

the higher value is:

so, the range of wavelength of infrared radiation is: