Mathematics, 01.08.2019 21:30 khuak877

Acoach is assessing the correlation between the number of hours spent practicing and the average number of points scored in a game. the table below shows the data: number of hours spent practicing (x) 0 0.5 1 1.5 2 2.5 3 3.5 4 score in the game (y) 5 8 11 14 17 20 23 26 29 part a: is there any correlation between the number of hours spent practicing and the score in the game? justify your answer. (4 points) part b: write a function which best fits the data. (3 points) part c: what does the slope and y-intercept of the plot indicate? (3 points)

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Part a.we can actually see that for every 0.5 increase in the value of x, there is a corresponding and constant increase of 3 in the value of y. so the answer to this is: yes and the correlation is linear. part b.the general form of a linear function is: y = m x + bwhere m is the slope and b is the y –intercept calculating for m using the formula: m = (y2 – y1) / (x2 – x1)m = (8 – 5) / (0.5 – 0)m = 3 / 0.5m = 6 the y-intercept b is the value of y when x = 0, therefore: b = 5 the complete equation of the function is: y = 6 x + 5 part c.the slope represents the rate of change, this means that there is an increase of 6 in the value of y for every increase of 1 in the value of x.

Answer from: amandavelez12122005

A. when the score is plotted on a graph against hours spent practicing, the points all fall on a straight line. this means there is perfect correlation between hours and score. (the correlation coefficient is r=1.)b. the regression function of the calculator shows the function to be.. score = 6*hours +5or.. y = 6x +5c. the slope is the score added for each additional hour of practice (6 points). the y-intercept is the score with no hours of practice.

Answer from: Quest

(2 x^3 + 7 x^2 + 5 x + 2)/(x (x + 2))

step-by-step explanation:

simplify the following:

x/x^2 + 3 x + 2 - (x (x + 1))/(x + 2)

combine powers. x/x^2 = x^(1 - 2):

x^(1 - 2) + 3 x + 2 - (x (x + 1))/(x + 2)

1 - 2 = -1:

x^(-1) + 3 x + 2 - (x (x + 1))/(x + 2)

put each term in 1/x + 3 x + 2 - (x (x + 1))/(x + 2) over the common denominator x (x + 2): 1/x + 3 x + 2 - (x (x + 1))/(x + 2) = (x + 2)/(x (x + 2)) + (3 x^2 (x + 2))/(x (x + 2)) + (2 x (x + 2))/(x (x + 2)) - (x^2 (x + 1))/(x (x + 2)):

(x + 2)/(x (x + 2)) + (3 x^2 (x + 2))/(x (x + 2)) + (2 x (x + 2))/(x (x + 2)) - (x^2 (x + 1))/(x (x + 2))

(x + 2)/(x (x + 2)) + (3 x^2 (x + 2))/(x (x + 2)) + (2 x (x + 2))/(x (x + 2)) - (x^2 (x + 1))/(x (x + 2)) = ((x + 2) + 3 x^2 (x + 2) + 2 x (x + 2) - x^2 (x + 1))/(x (x + 2)):

(2 + x + 3 x^2 (x + 2) + 2 x (x + 2) - x^2 (x + 1))/(x (x + 2))

3 x^2 (x + 2) = 3 x^3 + 6 x^2:

(2 + x + 3 x^3 + 6 x^2 + 2 x (x + 2) - x^2 (x + 1))/(x (x + 2))

2 x (x + 2) = 2 x^2 + 4 x:

(2 + x + 6 x^2 + 3 x^3 + 2 x^2 + 4 x - x^2 (x + 1))/(x (x + 2))

-x^2 (x + 1) = -x^2 - x^3:

(-x^2 - x^3 + 3 x^3 + 6 x^2 + 2 x^2 + 4 x + x + 2)/(x (x + 2))

grouping like terms, 3 x^3 - x^3 + 6 x^2 + 2 x^2 - x^2 + 4 x + x + 2 = (3 x^3 - x^3) + (6 x^2 + 2 x^2 - x^2) + (x + 4 x) + 2:

((3 x^3 - x^3) + (6 x^2 + 2 x^2 - x^2) + (x + 4 x) + 2)/(x (x + 2))

3 x^3 - x^3 = 2 x^3:

(2 x^3 + (6 x^2 + 2 x^2 - x^2) + (x + 4 x) + 2)/(x (x + 2))

6 x^2 + 2 x^2 - x^2 = 7 x^2:

(2 x^3 + 7 x^2 + (x + 4 x) + 2)/(x (x + 2))

x + 4 x = 5 x:

answer: (2 x^3 + 7 x^2 + 5 x + 2)/(x (x + 2))

Answer from: Quest

step-by-step explanation:

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