Chase plays the piano and the cello. for every 2 hours he practices the piano, he practices the cello for 3 hours. if he practiced the piano for 6 hours last week, how many hours did he spend practicing the cello?

if Chase practices 3hr of cello per every 2hrs of piano, first find how may times does 2hrs goes into the total 6hrs:

6 ÷ 2 = 3

Then multiply the number the hours of cello by the total 2 hours of 6;

3 × 3 = 9

so your final answer would be:  9 hours of cello

there are lots of ways.   pick's theorem tells us if the vertices are lattice points the area a is

a = b/2 + i - 1

where b is the number of boundary lattice points and i is the number of interior lattice points.

in the figure i count b=16, i=50 so

a = 8 + 50 - 1 = 57

let's try the shoelace formula.   the area is half the sum of the cross products of the sides.  

a(-2,6)   -2(2)-6(-5) = 26

b(-5,2)   -5(-3) - 2(-2) = 19

c(-2,-3) -2(-3) - (-3)(4) = 18

d(4,-3)   4(3) - (-3)(5) = 27

e(5,3)   5(3) - 3(1) = 12

f(1,3)     1(6) - 3(-2) = 12

a(-2,6)

each of the cross products is twice the area of the triangle with the associated side and one vertex the origin. so the area of abo=26/2=13.

area = (1/2) (26 + 19 +   18 + 27 + 12 + 12) = 57

that checks!

add all the numbers and check the ones place.

the answer is 486. as the ones place is more than 4, the estimation will be the next 10 ie, 490