Mathematics, 02.08.2019 03:30 loudenalexisp56lp0
Find the exact value of the trigonometric expression. sec pi/12 the answer is β6-β2, but i'm not sure how to get it.
Answers: 1
![\bf 2\sqrt{2+\sqrt{3}}(2-\sqrt{3})\impliedby \stackrel{\textit{keep in mind that}}{(2-\sqrt{3})=(\sqrt{2-\sqrt{3}})(\sqrt{2-\sqrt{3}})} \\\\\\ 2\sqrt{2+\sqrt{3}}\cdot \sqrt{2-\sqrt{3}}\cdot \sqrt{2-\sqrt{3}} \\\\\\ 2\sqrt{(2+\sqrt{3})(2-\sqrt{3})\cdot (2-\sqrt{3})} \\\\\\ 2\sqrt{[2^2-(\sqrt{3})^2]\cdot (2-\sqrt{3})}\implies 2\sqrt{1(2-\sqrt{3})} \\\\\\ 2\sqrt{2-\sqrt{3}}](/tpl/images/0160/3439/e1d6e.png)
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Find the exact value of the trigonometric expression. sec pi/12 the answer is β6-β2, but i'm not sur...
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