A$3000 deposit for 66 months compounded at an interest rate of 1.6% .

The correct question is

t=66 months >66/12=5.5 years

F = P*(1 +(r/m))^n

r=1.6% >0.016
m=12 (number of compounding periods per year)

n=m*t >12*5.5=66
we have
P=3000
t=5.5 years
F = 3000*(1 +(0.016/12))^66 >3275.77 dollars

 the answer is 3275.77 dollars 

.25

step-by-step explanation:

answer: he is 272195

step-by-step explanation: all you have to do is multiple 3535 and 77 and it equals 272195