Two buses leave a station at the same time and travel in opposite directions. one bus travels 14 /mih faster than the other. if the two buses are 496mi apart after 4 hours, what is the rate of each bus?

Let the speed of the slower bus be equal to x miles per hour
let the speed of the faster bus be equal to x+14 miles per hour
after every hour they would be a further 2x+14 miles apart from eachother
therefore after 4 hours they would be 4(2x+14) = 8x + 56 miles away from eachother
since we know exactly how many miles this is we can solve for x
8x + 56 = 496
8x = 440
x = 55
x + 14 = 69
therefore, the speed of the slower bus is 55 mph whereas the speed of the faster bus is 69 mph

Ifound this on google “a skewed (non-symmetric) distribution is a distribution in which there is no such mirror-imaging. a "skewed right" distribution is one in which the tail is on the right side. a "skewed left" distribution is one in which the tail is on the left side. the above histogram is for a distribution that is skewed right.” i hope this you for what your looking for