Amachine grinds 2/7 pound of spices in 1/3 second. what is the machines rate, in pounds per second of grinding spice

Firstly it is important to look at all the information's that are given in the question. Based on those information's the answer to the question can be easily deduced.
In 1/3 second the quantity of spices ground by the machine = 2/7 pound
In 1 second the quantity of spices ground by the machine = (2/7)/(1/3) pound
                                                                                             = (2/7) * 3 pound
                                                                                             = 6/7 pound
So the rate at which the machine grinds spices is 6/7 pounds per second.I hope the procedure of doing this problem is clear to you and the answer has been correctly deduced. Just be careful while dividing the numbers (2/7) and (1/3). Then there is no issue with this question. I hoped to have come to your help.

When rates are expressed as a quantity of 1, such as 2 feet per second or 5 miles per hour, they are called unit rates. if you have a multiple-unit rate such as 120 students for every 3 buses, and want to find the single-unit rate, write a ratio equal to the multiple-unit rate with 1 as the second term.

What exactly is your question?