The table shows the position of a motorcyclist after accelerating from rest. find the average velocity for each time period: (2, 4)

The average velocity for each time period: (2, 4) is 29.3 ft/s

The table shows the position of a motorcyclist after accelerating from rest. find the average velocity for each time period: (2, 4)

The velocity of an object is the rate of change of its position with respect to a frame of reference, and is a function of time. Velocity is a vector quantity, then average velocity can be defined as the displacement divided by the time.

The average velocity over the time interval [t,t+h] is

First we obtain the average velocity over the time interval [2,4]

Then subsitute t=2 and t+h = 4 in equation v_avg above

From the table attached, we can know

When t=2 sec,

When t=4 sec,

Thus the average velocity over the time interval [2,4] is

Therefore the average velocity for each time period: (2, 4) is 29.3 ft/s

Grade:    5

Subject:  Math

Chapter:   the  velocity

Keywords: the average velocity, accelerating, position, motorcyclist, time period

the table in the attached figure

we need to find the average rates of change over each time interval

a)  [1, 3]    for t=1 seg  s=1.4 m  (1,1.4)  for t=3 seg  s=10.7 m  (3,10.7)

     v=(10.7-1.4)/(3-1)=9.3/2=4.65 m/seg

b)  [2, 3]    for t=2 seg  s=5.1 m  (2,5.1)  for t=3 seg  s=10.7 m  (3,10.7)

     v=(10.7-5.1)/(3-2)=5.6/1=5.6 m/seg      

c)  [3, 5]    for t=3 seg  s=10.7 m  (3,10.7)  for t=5 seg  s=25.8 m  (5,25.8)

     v=(25.8-10.7)/(5-3)=15.1/2=7.55 m/seg  

d)  [3, 4]    for t=3 seg  s=10.7 m  (3,10.7)  for t=4 seg  s=17.7 m  (4,17.7)

     v=(17.7-10.7)/(4-3)=7/1=7 m/seg  

1)is not similar since corresponding sides are not in the same ratio

2)are similar since corresponding sides are in the same ratio and corresponding angles are equal

hope it will

#faazmessi

step-by-step explanation:

the original amount doesn't ''re just looking for the time it takes for 1/2 of the substance to we have

(1/2) =)     take the ln   of both sides

ln (1/2)   = )   and we can write

ln(1/2) = ) lne     and lne   = 1     so we have

ln(1/2) = -.1092t     divide both sides by -.1092

t = ln(1/2)/-.1092 = about 6.347 days = about 6.3 days (rounded)