Prove that (n+5)^2(n+3)^2 is a multiply of 4

Solve for n:
(n + 3)^2 (n + 5)^2 = 0

Split into two equations:
(n + 3)^2 = 0 or (n + 5)^2 = 0

Take the square root of both sides:
n + 3 = 0 or (n + 5)^2 = 0

Subtract 3 from both sides:
n = -3 or (n + 5)^2 = 0

Take the square root of both sides:
n = -3 or n + 5 = 0
Subtract 5 from both sides:
  n = -3 or n = -5  thus the Answer is wrong, neither -3 or -5 are a multiple of 4

21/2 or 5/2