Which of the following trigonometric functions, restricted to 0 < x < π, have values greater than 1? f (x) = sin xf (x) = cos xf (x) = cot xf (x) = sec x

We will evaluate each function separately in the given interval:
 0 <x <π
 f (x) = sin x
 f (0) = sin 0 = 0
 f (π) = sin π = 0

 f (x) = cos x
 f (0) = cos 0 = 1
 f (π) = cos π = -1

 f (x) = cot x
 f (0) = cot 0 = Cos0 / sin0 = 1/0 = inf
 f (π) = cot π = Cosπ / sinπ = -1 / 0 = -inf
 We can observe that the function f (x) = cot x tends to infinity when it approaches zero.

 f (x) = sec x
 f (π / 2) = sec π / 2 = 1 / cos π / 2 = 1/0 = inf
 We can observe that this function has values that tend towards infinity when it approaches π / 2

 
 this function has values greater than 1 in 0 <x <π
 f (x) = sec x

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