Part 1 : solve the following equations. check your solutions. me with this plz

Hey there! :D

Let's start with the first one. 

1.) 3b-2=13

You need to balance the equation and do the opposite to the other side. To get rid of the 2, we would have to add 2 to both sides. 

3b-2(+2)=13(+2)

3b=15

Divide both sides by 3. (the inverse of multiplication) 

b=5

Now, check it by plugging it in. 

3b-2=15
3(5)-2=13
15-2=13
13=13 <== this works

Let's try another:

2.) 4a+2-a+10= 33

Combine like terms. 

4a-a=3a

2+10=12

3a+12= 33

Subtract 12 on both sides. 

3a=21

Divide both sides by 3.

a=7

Check our work:

4a+2-a+10=33
4(7)+2-7+10=33
28+2-7+10=33
30-7+10=33
23+10=33
33=33 <=== this works

Let's try one more, and you can try the last one. 

3.) 2(w-3)+6w=10

Distribute. (multiply 2 to w and -3)

2*w=2w

2*-3=-6

2w-6+6w=10

Combine like terms. 

8w-6=10

Add 6 to both sides. 

8w=16

Divide both sides by 8. 

w=2

Check your work:

2(w-3)+6w=10
2(2-3)+6(2)=10
4-6+12=10
-2+12=10
10=10 <== this works

I hope this helps! Have a great day. 
~kaikers