How do you answer this for a elimination simulatoneons equation

Therefore, the solution is:  x = 4,  y=1.

First you multiply both equations by 5 and 3
Then you take away both the equations form one another
Next you divide by 4 to get y on its own
This gives you y - which is 4

Then you choose one equation from your question. I chose 3x + 2y = 14 because it looks easier
Input your y value (that you just worked out before) into the y on this equation
Get x on its own by minusing 8 then dividing by 3
This gives you x - which is 2

Ive put a picture incase you still do not understand

Intersecting secant-tangent theorem states that if a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.so to break it down: 1. pq acts as the tangent and ps as the secant with an intersection at p.sr = 21rp = 3x + 3pq = 4x + 4following to equation: tangent squared = the two segments multiplied by each otherso (4x + 4) ^ 2 = (3x + 3) • (21) simplifies to 16x^2 - 31x - 47 = 0 or (16x - 47)(x + 1) x = -1 or x = 47/162. pq acts as the tangent and ps as the secant with an intersection at p (again! )sr = 16rp = xpq = 15(15) ^ 2 = 16 • x225 = 16xx = 225/163. the interesting chords are proportional to each other so a ratio is possible to set up: ap dp 10 3 + x = = —— = pc pb 8 xcross multiple to get 10x = (3 + x)(8)x = 12