The five members of the traynor family each buy train tickets. during the train ride, each family member buys a boxed lunch for $6.50. if the total cost of the trip is $248.50, what is the price of each train ticket?

Let's assume

the price of each train ticket is x

we are given

total number of family members =5

so, total cost of ticket = total number of family members*the price of each ticket

so, total cost of ticket =5*x

so, total cost of ticket =5x

now, we have

each family member buys a boxed lunch for $6.50

so, total cost of lunch box = total number of family members*price of each lunch box

so, total cost of lunch box = 5*6.50

total cost of trip = total cost of ticket+total cost of lunch box

we are given

total cost of trip is $248.50

now, we can plug values

and we get

now, we can solve for x

so,

the price of each train ticket is $43.2..........Answer

The price of each train ticket can be calculated by generating the algebraic expression as per the question.

The price of each train ticket is $43.2.

Given:

The family member is 5.

The lunch box cost is $6.50.

The total cost of the trip is $248.50.

Let price of each train ticket is .

The total cost of ticket is multiplication of  total number of family members and the price of each ticket.The mathematical expression is,

Write the expression for total cost of trip.

Thus, the price of each train ticket is $43.2.

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