Find the remaining trigonometric ratios of θ if csc(θ) = -6 and cos(θ) is positive

Now, the cosecant of θ is -6, or namely -6/1.

however, the cosecant is really the hypotenuse/opposite, but the hypotenuse is never negative, since is just a distance unit from the center of the circle, so in the fraction -6/1, the negative must be the 1, or 6/-1 then.

we know the cosine is positive, and we know the opposite side is -1, or negative, the only happens in the IV quadrant, so θ is in the IV quadrant, now



recall that 



therefore, let's just plug that on the remaining ones,



now, let's rationalize the denominator on tangent and secant,