Pat run an animal shelte. the actual number of animals brought in during a particular month was 150. the percent error was 12%. if pat estimated on the high side (more than 150), how many animals did pat think were brought to the shelter

Let us assume the number of animals that Pat miscalculated = x
The number of actual animals bought during a particular month = 150
Percentage of error that was made by Pat = 12%
Number of animals miscalculated by Pat can be written as
100x/12 = 150
100x = 150 * 12
x = 1800/100
   = 18
Then
The the number of animals that Pat thought were brought to the shelter = 150 + 18
                                                                                                                   = 168
So Pat miscalculated the number of animals that were brought to the shelter was 168.

It’s d for sure i just did also that’s why