Arectangular room is 3 3 times as long as it is wide, and its perimeter is 64 64 meters. find the dimension of the room.

Perimeter = 2L + 2W    (where L = length and W = width)

And we are given that L = 3W

So substituting for L, we have the equation:-

2(3W) + 2W = 64

6W + 2W = 64

8W = 64 

W = 8  meters

So the length = 3*8  = 24 meters

- Length = 24 m and Width = 8 m.