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Mathematics, 03.08.2019 10:00 kmoo176394

Need asap the tables below show the values of f(x) and g(x) for different values of x: f(x) = 2(3)x x f(x) βˆ’2 0.22 βˆ’1 0.67 0 2 1 6 2 18 g(x) = 3x + 1 x g(x) βˆ’2 1.11 βˆ’1 1.33 0 2 1 4 2 10 based on the tables, what is the solution to the equation 2(3)x = 3x + 1? x = βˆ’1 x = 0 x = 1 x = 2

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