The length and width of a rectangle are consecutive odd integers. the perimeter is 64 meters. find the length and width.

width = 15 meters and length = 17 meters

Step-by-step explanation: To solve this problem, our first task is to set up variables for the width and length.

Since the width and length are consecutive odd integers, let's call the width of the rectangle X and the length of the rectangle X + 2.

To help set up our equation, I will provide a picture of the rectangle with the length and with labeled.

Since the perimeter of the rectangle is 64 meters, we can represent this with our equation which is as followed. Remember, perimeter is the distance around the rectangle.

X + X + (X + 2) + (X + 2) = 64

4x + 4 = 64   ← simplify on the left side

      -4    -4   ← subtract 4 from both sides

4x = 60

÷4   ÷4   ← divide both sides by 4

X = 15

width ⇒ X = 15

length ⇒ X + 2 = 17

Therefore, the width of the rectangle is 15 meters and the length of the rectangle is 17 meters.

answer: i cant see the picture

step-by-step explanation:

can u take a better picture

2. angles qrt and qst both measures 156 degrees.

step-by-step explanation:  

we have been given a diagram of a circle and we are told that measure of arc qvt is 156 degrees.  

we can see from our given diagram that angle qrt and angle qst subtends to arc qvt.

since we know that angles subtended by the same arc at the circumference are always equal.

by angle subtended by same arc theorem, measure of angle qrt and angle qst will be equal to the measure of arc qvt.

therefore, angles qrt and qst both measures 156 degrees and 2nd statement is the correct choice.