Mathematics, 03.08.2019 17:30 merzedes
If 3x^2 + y^2 = 7 then evaluate d^2y/dx^2 when x = 1 and y = 2. round your answer to 2 decimal places. use the hyphen symbol, -, for negative values.
Answers: 1
and differentiating both sides with respect to 
yields![\dfrac{\mathrm d}{\mathrm dx}\bigg[3x^2+y^2\bigg]=\dfrac{\mathrm d}{\mathrm dx}\bigg[7\bigg]\implies 6x+2y\dfrac{\mathrm dy}{\mathrm dx}=0](/tpl/images/0166/4137/562c6.png)
![\dfrac{\mathrm d}{\mathrm dx}\bigg[6x+2y\dfrac{\mathrm dy}{\mathrm dx}\bigg]=\dfrac{\mathrm d}{\mathrm dx}\bigg[0\bigg]\implies 6+2\left(\dfrac{\mathrm dy}{\mathrm dx}\right)^2+2y\dfrac{\mathrm d^2y}{\mathrm dx^2}=0](/tpl/images/0166/4137/d8d91.png)
and 
, we have
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If 3x^2 + y^2 = 7 then evaluate d^2y/dx^2 when x = 1 and y = 2. round your answer to 2 decimal place...
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