Aline passes through point (-2, 5) and has a slope of 2/3. points a(x, 3) and b(-2, y) lie on the line what are the x and y values

Equation of the line is 
y-5 = 2/3 (x+2)
y-5= (2/3)x +4/3
y=(2/3)x +4/3+15/3
y=(2/3)x +19/3

if A (x,3) belongs to the line then we substitute y=3 in the equation of the line to find out x
3=(2/3)x +19/3
(9/3)-19/3 =(2/3)x
-10/3=2x/3
x= -10/2=-5
A( -5, 3)

if B (-2, y) belongs to the line then we substitute x= -2 in the equation of the line to find out y
y=(2/3)(-2) +19/3
y=-4/3+19/3
y=15/3=5
B (-2 , 5)

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