In abc, ab = x, bc = y, and ca = 2x. a similarity transformation with a scale factor of 0.5 maps abc to mno, such that vertices m, n, and o correspond to a, b, and c, respectively. if om = 5, what is ab?

we have 
AB = xwith a scale factor of 0.5= x*0.5=0.5x
BC = ywith a scale factor of 0.5= y*0.5=0.5y
CA = 2xwith a scale factor of 0.5= 2x*0.5=x

AB with a scale factor = MN
BC with a scale factor =  NO
AC with a scale factor = OM

 MN=0.5x

NO=0.5y

OM=AC=x=5

X=5
AB=x=5

The answer is AB=5

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

one that is bigger than 3 1/2