Aclassroom has two rows of 8 seats each. there are 14 students, 5 of whom always sit in the front row and 4 of whom always sit in the back row. in how many ways can the students be seated.

  28,449,792,000

Step-by-step explanation:

There are 8P5 = 6720 ways the five students who sit on the front row can arrange themselves.

There are 8P4 = 1680 ways the four students who sit on the back row can arrange themselves.

In the remaining 7 seats, there are 7P5 = 2520 ways the remaining 5 students can arrange themselves.

The total number of possible arrangements of students (with the given limitations) is ...

  6720·1680·2520 = 28,449,792,000

nPk = n!/(n-k)!

so 8P5 = 8!/3! = 8·7·6·5·4 = 6720

describing distributions is one of the key skills you’ll need to earn a high score on the ap statistics exam. if you need proof of this, just flip through some past exam questions, which can be found at the collegeboard website. you’ll notice that the first free response question is almost always a question requiring you to look at a graph and describe it.

step-by-step explanation: just trying to get points sorry : (