This figure is made up of a rectangle and parallelogram.

what is the area of this figure?

enter your answer in the box. do not round any side lengths.

units²

40 units^2
   The figure has the vertexes (2,7), (3,3), (3,-3), (-5,-5), (-6,-1), and (2,1). If you draw a line from (2,1) to (3,-3) you'll divide the figure into the rectangle and parallelogram. The total area will be the sum of the area of the parallelogram and the rectangle. The area of the parallelogram will be base times height, where the height is the distance between the line (2,7) to (2,1) and line (3,3) to (3,-3) which is 1 and the base is the length of the line (2,7) to (2,1) which is 6. So the parallelogram has an area of 6.

   The length and width of the rectangle can be calculated from the Pythagorean theorem, so:
 L = sqrt((2- -6)^2 + (1- -1)^2) = sqrt(8^2 + 2^2) = sqrt(64+4) = sqrt(68) = 2*sqrt(17)
 W = sqrt((-6 - -5)^2 + (-1 - -5)^2) = sqrt(-1^2 + 4^2) = sqrt(1 + 16) = sqrt(17)

So the area of the rectangle is 2*sqrt(17)*sqrt(17) = 2*17 = 34. And the total area is 34 + 6 = 40.

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