What is the oblique asymptote of the function f(x) = the quantity x squared plus 5x plus 6 over the quantity x minus 4? y = x + 9 y = x − 9 y = x + 1 y = x − 1

Answer y = x+9

Given function f(x) =

To find out oblique asymptote we use long division

We divide x^2 + 5x + 6 by x-4

Hereby attached a file that shows long division

Long division steps are given below

1. Divide the first term of both numerator by denominator (x^2/x = x)

2. Multiply the answer x with x-4 that gives x^2 - 4x and put it at the bottom

3. Change the sign and subtract it

4. Repeat the step 1,2,3 till we get the remainder

We got quotient is x+9

So we write oblique asymptote y = x+9

7. d. 64

8. i. 32

9. c. 125

10. j. none of the above

11. d. 81

12. i. 216

13. e. none of the above

14. g. 240

15. e. none of the above

16. g. 32

17.   e. none of the above

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step-by-step explanation: