Given that eb bisects cea, which statements must be true? check all that apply.

Consider all options:

1. m∠CEA=90°. This option is true, because

2. ∠CEF is straight angle, then m∠CEF=180°. If bisects right angle ∠CEA, then

m∠CEB=m∠BEA=45°.

Therefore,

m∠BEF=m∠BEA+m∠AEF=45°+90°=135°.

Then m∠CEA+m∠BEF=90°+135°=225° ≠ 180°=m∠CEF.

This option is false.

3. m∠CEB=45° and m∠CEA=90°, then m∠CEB≠2m∠CEA.

This option is false.

4. From the part B you can see that m∠BEF=135°. This option is true.

5. ∠CEF is straight angle, this option is true.

6. Since then ∠AEF is right angle. This option is true.

true options are 1, 4, 5 and 6.

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!

just needed some points but try socratic