In a geometry class, there are 28 students. of the 28 students, 15 students are male and 13 students are female. on a recent exam, 9 female students passed the exam and 13 male students passed the exam. if a student from the class is chosen at random, what is the probability that the student will be a male or passed the exam?

6/7

Explanation:

1) Do a table with the given data

                   male       female    total
passed        13               9         
failed                                         
total             15              13        28

2) complete the table calculating the missing information:

                   male       female    total
passed        13               9         22 
failed             2               4           6     
total             15              13        28

3) Probaility that a student will be a male: 15 / 28

4) probability that the student passed = 22 / 28

5) probability that a student will be a male or passed = probability that a student will be a male + probaility that the studen passed - probability that the student will be a male and passed

probability that the student will be a male and passed = 13 / 28

probability that a student will be a male or passed = 15 / 28 + 22 / 28 - 13 /28 =

= 24 / 28 = 6/7

6/7

(-14+3/2b) - (1+8/2b) = -5 -5/2b(-10+b) + (7b-5) = 8b-15(7/2b-3) - (8+6b) = -5/2b-11(5+2b) + (2b+3/2) = 4b+ 13/2