Y= x2  + 3x - 10  for the above quadratic equation find:   a. the y-intercept.  b. the x-intercepts if possible.  c. the vertex.  d. the line of symmetry.

Note:  y = x2 + 3x - 10   should be    y = x^2 + 3x - 10, where " ^ " indicates exponentiation.

To find the y-int.:  Let x = 0 and find y.  That intercept is (0, -10).
To find the x-int.:  Set  y = x^2 + 3x - 10 = to 0, and solve for x.  You could, for example, use the quadratic formula, completing the square, graphing, factoring, etc.   x^2 + 3x - 10 = 0 can be factored easily:

(x+5)(x-2)=0, so that x = -5 and x=2.  The x-int. are (-5,0) and (2,0).

The x-coord. of the vertex can be found by using the formula x = -b/(2a).
Once you have that, subst. that result into the given formula and calculate y.

The line of symm. has precisely the same form:  x = -b/(2a), where
b=3 and a = 1.  Here we don't need or care about c= -10.

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