Provide the missing reasons for the proof of part of the triangle midsegment theorem.

given: k is the midpoint of mj. l is the midpoint of nj.

prove: mn = 2kl

statement:
1.) k is the midpoint of mj. l is the midpoint of nj.

2.) mk ≅ kj and nl ≅ lj

3.) mk = kj and nl = lj

4.) mj = mk + kj and nj = nl + lj

5.) mj = 2kj and nj = 2lj

6.) mj/kj = nj/lj = 2

7.)
8.) triangle jmn ~ triangle jkl

9.) mn/kl = mj/kj

10.) mn/kl = 2

11.) mn = 2kl

reason:

1.) given
2.)
3.)
4.)
5.) substitution property of equality
6.) division property of equality
7.)
8.)
9.)
10.)
11.)

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!

the answer would be 1 1/72

step-by-step explanation:

you can rewrite the equation by separating the parts and then solving individually:

10-9=1

1/8 - 1/9=

find l c d and then combine:

1 1/72