Mukul has $3.75 in quarters, dimes and nickels in his pocket. he has five more dimes than quarters and nine more nickels than quarters. how many of each coin are in his pocket?

There are 7 coins of quarters , 12 coins of dimes and 16 coins of nickels .

Step-by-step explanation:

Mukul has $3.75

1 dollar = 100 cents

3.75 dollar = 375 cents

Let he has x coins of quarters

Since we are given that he has five more dimes than quarters.

So, Dimes = x+5

Since we are given that he has nine more nickels than quarters .

So, nickels = x+9

Now 1 quarter = 25 cents

So, x quarter = 25 x cents

1 dime = 10 cents

So, (x+5) dimes = 10(x+5) cents

1 nickel = 5 cents

So, (x+9) nickels = 5(x+9) cents.

Since he had 375 cents in total .

Thus there are 7 coins of quarters

Coins of dimes = x+5=7+5=12

Coins of nickels = x+9=7+9 =16

Hence there are 7 coins of quarters , 12 coins of dimes and 16 coins of nickels .

for the points! : )

b. astronomers