The hypotenuse of a right triangle is 8 cm long. one leg is 2 cm longer than the other. find the length of the longer leg to the nearest tenth.

General formula to find the sides of right triangle is
a² + b² = c²
c stands for the hypotenuse

We can assume a stands for the shorter leg and b is the longer leg, the equation will be
b = a + 2
a = b - 2

Now input the number to the formula
a² + b² = c²
(b-2)² + b² = 8²
b² - 4b + 4 + b² = 64
2b² - 4b + 4 - 64 = 0
2b² - 4b - 60 = 0
b² - 2b - 30 = 0

Work the equation by completing the square
b² - 2b - 30 = 0
b² - 2b = 30
b² - 2b + 1 = 30 + 1
(b + 1)² = 31
b + 1 = √31
b = -1 + √31
b = -1 + 5.5678
b = 4.5678
b = 4.6
The longer leg is approximately 4.6

-2x + 7 = 7

subtract 7 from both sides.

-2x = 0

divide both sides by -2.

x = 0

the value of x is equal to 0.