Which answers describe the end behaviors of the function modeled by the graph?

f(x)=(12)x+1−2f(x)=(12)x+1−2
select each correct answer.

as x decreases without bound, f(x) increases without bound.

as x increases without bound, f(x) approaches the line y=−2y=−2 .

as x decreases without bound, f(x) approaches the line y=−2y=−2 .

as x decreases without bound, f(x) decreases without bound.

Options 1 and 2 are correct.

Step-by-step explanation:

The graph represents the function

From the given graph it is noticed that the value of f(x) approaches to infinity as x approaches to negative infinity and the value of f(x) approaches to -2 as x approaches to positive infinity.

It can also represented by limits.

As x increases without bound

Apply limit.

As x decreases without bound

Apply limit.

Therefore as x decreases without bound, f(x) increases without bound and as x increases without bound, f(x) approaches the line y=−2. Options 1 and 2 are correct.

anser is a

step-by-step explanation:

negitive slope

faster, im not sure why but i know it is faster