Abin of 50 parts contains 5 that are defective. a sample of 10 parts is selected at random, without replacement. how many samples contain at least four defective parts.

41,947,059 samples contain at least four defective parts.

Step-by-step explanation:

The order of the parts are not important, and they are chosen without replacement. So the combinations formula is used to solve this question.

Combinations formula:

is the number of different combinations of x objects from a set of n elements, given by the following formula.

4 defective parts:

There are 10 parts chosen, of 50 in total.

We want 4 defective, from a set of 5.

And 10-4 = 6 non-defective, from a set of 50-5 = 45. So

5 defective parts:

5 defective, from a set of 5.

5 non-defective, from a set of 45. So

How many samples contain at least four defective parts.

40725300 + 1221759 = 41,947,059

41,947,059 contain at least four defective parts.

x= cost per bracelet

number of bracelets * x + shipping charge = total cost

so

9x+9=72

explanation:

remove parenthesis:

=

apply rule

=

multiply fractions:

=

=

divide:

=

mordancy.