~~-~~(x^3-2x+1)}{2\sqrt{x}}}{x} \\\\\\ \cfrac{dy}{dx}=\cfrac{\frac{[(3x^2-2)2x]~~-~~(x^3-2x+1)}{2\sqrt{x}}}{x} \implies \cfrac{dy}{dx}=\cfrac{\frac{[6x^3-4x]~~-~~(x^3-2x+1)}{2\sqrt{x}}}{x}](/tpl/images/0271/2966/6aa46.png)
How to find the derivative of this function?
i keep getting the answer wrong, could som...
Mathematics, 28.09.2019 15:20 thechameleonnaire
How to find the derivative of this function?
i keep getting the answer wrong, could someone pls explain this step by step?
you
Answers: 1
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