Suppose a triangle has sides a, b, and c, and let (/) be the angle opposite the side of length a. if cos(/) > 0 what must be true? a. b^2 + c^2 < a^2 b. a^2 + b^2 = c^2 c. b^2 + c^2 > a^2 d. a^2 + b^2 > c^2

 a² =  b² +  c² -2 bc cos (/)

 Simplifying the equation in terms of cos (/),

 cos (/)= (b² + c² - a²)/(2bc) 

 If cos(/) > 0

 (b² + c² - a²)/(2bc) > 0 (b² + c² - a²) > 0 

the resulting inequality should be

x/3-10=8

x/3=18

x=48