Triangle abc has vertices a(0,0), b(0,4), and c(3,0). write the equation for the line containing altitude ar in standard form.

y = (3/4) x

Explanation:
The general form of the linear line is:
y = mx + c where m is the slope and c is the y-intercept
Step 1: getting the slope:
Since AR is the altitude of ABC, therefore, AR is perpendicular on BC which means that slope of AR = -1/slope of BC
Therefore, we will need to get slope of BC:
We have point B = (0,4) and point C = (3,0)
slope of BC = (y2-y1) / (x2-x1) = (0-4) / (3-0) = -4/3
This means that:
slope of AR = m = 3/4
Step 2: getting the y-intercept:
Since point A belongs to the altitude, therefore, point A satisfies the equation of the line. So, to get the y-intercept, we will use point A to substitute in the equation of the line and solve for c as follows:
y = mx + c
y = (3/4) x + c
0 = (3/4)(0) + c
c = 0

Based on the above, equation of the line is:
y = (3/4) x

Hope this helps :)

Iam guessing c. or d.