Bob is a high school basketball player. he is a 70% free throw shooter. that means his probability of making a free throw is 0.70. during the season, what is the probability that bob makes his third free throw on his fifth shot? what is e(x)?

P =Probability of making free throw by Bob = 70 % = 0.70

Q=Probability that bob will be not able to make a free throw = 1 - 0.70= 0.30

Probability, that bob makes his third free throw on his fifth shot

                  = Taking fifth throw as free throw and Remaining 4 throws in which (two are free throw=P) and (2 are not free throw=Q)

          = ways

        = 6×Q²× P³

        = 6 × (0.30)²×(0.70)³

   e(x)  =  0.18522 (Approx)

the k side

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plese mark mde brainliest!

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