Y= x2 - 5x - 3
6x - y = -27
y = x2 - 5x + 3
6x - y = 27
y = x2 + 5x + 3
6x + y = -27
y = x2 + 5x - 3
6x + y = 27

Need ! give step by step solutions on how to solve number one [tex]\frac{9-2\sqrt{3} }{12+\sqrt{3} }[/tex] number two [tex]x+4=\sqrt{13x-20}[/tex] number three (domain and range) [tex]f(x)=2\sqrt[3]{x} +1[/tex]

Read the equations in the table below. then drag a description of the situation and a table to represent each equation. indicate whether each of the relationships is proportional or non-proportional.

What describes horizontal cross section of the right rectangle 6m 8m 5m