What is an equation for the linear function whose graph contains the points (−1, −2) and (3, 10)? enter your answers in the boxes. y+ = (x+1)

Find the slope of this graph; it is    
        10+1
m = = 11/4.
        3+1

Using the slope-intercept formula:  y = mx + b becomes 10=(11/4)(3 + b

Then 40 = 11(3) + 4b, or 7 = 4b, or b = 7/4 

Then the equation of this graph is    y = (11/4)x + 7/4.

The answer is 63.!

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