Afarmer raised 60 goats, then entered into a series of business transactions. he traded all the goats for sheep at an exchange rate of 5 goats for 7 sheep. next, he exchanged all the sheep for hogs at a a rate of 4 sheep for 2 hogs weighing 250 lbs. each. he sold all the hogs at a market price of $55.00 per 100.0 lbs. how much money did he make from the 60 hogs?

Solution:

we are given that

A farmer raised 60 goats, then entered into a series of business transactions. He traded all the goats for sheep at an exchange rate of 5 goats for 7 sheep.

since

It mean he get ships in exchange.

Next, he exchanged all the sheep for hogs at a a rate of 4 sheep for 2 hogs weighing 250 lbs.

Again

It mean he get hogs in exchange.

Each weighing 250 lbs.

So Total weight of 42 hogs lb

He sold all the hogs at a market price of $55.00 per 100.0 lbs.

Again

So he get $

So total money he made =5775$

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!

24

step-by-step explanation:

the graph shows 30% of students walk. 80 students were questioned, so the number that said they walk is

30% × 80 = 0.30 × 80 = 24