The heights of adult women are approximately normally distributed about a mean of 65 inches with a standard deviation of 2 inches. if rachael is at the 99th percentile in height for adult women, then her height, in inches, is closest to:

Using the normal distribution, it is found that her height is of 69.7 inches.

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In a normal distribution with mean and standard deviation , the z-score of a measure X is given by:

In this problem:

Her height is of 69.7 inches.

A similar problem is given at link

69.65 inches

Step-by-step explanation:

Mean =

Standard deviation =

Now we are supposed to find if Rachael is at the 99th percentile in height for adult women, then her height, in inches

Formula :

z at 99th percentile =2.326

Substitute the values in the formula

Hence her height is 69.65 inches .

1.true 2.false? ? i think. .

step-by-step explanation:

found it xd it ok yt