What is a counterexample for the conjecture conjecture any number that is divisible by 2 is also divisible by 4?

Step-by-step explanation:

A counter-explample can be defined, in logic, as an exception to the rule, in this case, an example that shows the conjecture is wrong. This method is used to demonstrated a given "function" or statement.

So, we just need to find one case where a number can be divided by 2 but not by 4, which is 66, because

Therefore, the conjecture is wrong, because there's a case where a number can be divided by 2 but not by 4.

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

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step-by-step explanation: