Write an equation for a circle with a diameter that has endpoints at (–10, 1) and (–8, 5). round to the nearest tenth if necessary

The standard form for the equation of a circle is :

 So the midpoint of the diameter with endpoints at (−10,1)and(−8,5) is :

 ((−10+(−8))/2,(1+5)/2)=(−9,3)

 So the point (−9,3) is the center of the circle.

  Now, use the distance formula to find the radius of the circle:

  r^2=(−10−(−9))^2+(1−3)^2=1+4=5

 ⇒r=√5

 Subtituting h=−9, k=3 and r=√5 into EQ(1) gives :

 (x+9)^2+(y−3)^2=5

step-by-step explanation:

no, her answer is not correct.   we square the lengths of all sides and then determine whether the pythagorean theorem holds here:

9² + 15² = 306.   this is not equal to the square of the longest side ( that square being 395.   answer c is correct.

his first public project he is asked to create a small scale drawing. the garden is a right triangle with base 25m and height 30m. are you trying to solve for the last side/hypotenuse? the irrational form of the answer would be 5\sqrt{61}