An equation for this question? perpendicular p(2,8) y=2x+1

Y = 2x + 1the slope here is 2. A perpendicular line will have a negative reciprocal slope. To find the negative reciprocal, u flip the slope and change the sign. So the slope is 2 or 2/1flip it and it becomes 1/2change the sign and it becomes -1/2. So ur perpendicular line will have a slope of -1/2.

y = mx + b
slope(m) = -1/2
(2,8)x = 2 and y = 8
now sub into the formula and find b, the y int
8 = -1/2(2) + b
8 = -1 + b
8 + 1 = b
9 = b
so ur perpendicular equation is : y = -1/2x + 9 <

ur y int is (0,9)to find the x int, sub in 0 for y and solve for x
0 = -1/2x + 9
1/2x = 9
x = 9 * 2
x = 18...so ur x int is (18,0)...but ur graph doesn't go this far

to graphur y int (where the line crosses the y axis) is at (0,9)..and since u have a slope of -1/2, u come down 1 space, and to the right 2 spaces...plot thatthen down 1, and to the right 2...plot thatkeep doing this and u would cross the x axis at (18,0) if it went that farthen just connect ur plotted points and u have ur line

Whose mistake? can you give more details to what the question is asking?