Find the equation of a line that passes through the point (2,1) and has a gradient of 2 leave your answer in the form of y=mx+c

y= 2x - 3

Step by step solution:

Y = mx + c  

Where

y= y coordinate

m = gradient (it is known as steepness of the slope)

x= x coordinate  

c = y intercept  

m = 2

c = ?

x = 2

y = 1

Substitute the values in the above equation  

y = mx + c  

1 = 2 (2) + c

1 = 4 + c

1 – 4 = c

-3 = c

y = 2x - 3

see attached

step-by-step explanation:

given the function as;

write the equation replacing f(x) with y

form   and fill a table containing values of y with corresponding values of x

you can take a range for   values of x as -3≤x≤3

solving for x=-3

for x=-2

repeat the same procedure to get the values of y for the remaining ,x=-1 to x=3

plot the values of y against values   of x and obtain the following graph

answer: your answer is c

step-by-step explanation: