Arectangular yard has an area of 96 square feet. if the width of the yard is 4 feet less than the length, what is the perimeter, in feet, of the yard?

  40 ft

Step-by-step explanation:

Let x represent the average of the length and width. Then the length is (x+2) and the width is (x-2). The area is the product of these:

  96 = (x +2)(x -2) = x² -4

  100 = x² . . . . . . add 4

  10 = x . . . . . . . . square root

Since x is the average of two numbers, their sum is 2x. The perimeter of the yard is twice the sum of length and width, so is 4x = 4·10 = 40.

The perimeter of the yard is 40 feet.

In case you care, the size of the yard is 8 ft by 12 ft.

g = (2, 2)

step-by-step explanation:

given the ratio is 1 : 1 then f is the midpoint of eg

let the coordinates of g = (x, y)

using the midpoint formula

(0 + x) = 1 ( multiply both sides by 2 )

0 + x = 2 ⇒ x = 2

similarly

(4 + y) = 3 ( multiply both sides by 2 )

4 + y = 6 ( subtract 4 from both sides )

y = 2

coordinates of g = (2, 2)

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step-by-step explanation: