The ransin sports company has noted that the size of individual customer orders is normally distributed with a mean of $112 and a variance of $9. if a soccer team of 16 players were to make the next batch of orders, what would be the standard error of the mean?

Standard error of the mean is computed by:

Standard error = SD/ sqrt N

Where:

N is the sample size

SD is the standard deviation

To get the standard deviation, you need to get the sqrt of the variance = sqrt 9 = 3

So plugging in our data:

Standard error = 3 / sqrt (16)

= 0.75

56.6

step-by-step explanation:

the ratio of the perimeters is equal to the scale.

the ratio of the areas is equal to the square of the scale.

34 / 20 = k

a / 19.6 = k²

substituting:

a / 19.6 = (34 / 20)²

a = 19.6 (34 / 20)²

a ≈ 56.6