What is limits as x approaches negative 7 from the left of the quotient of x and the quantity x plus 7.? 0 −∞ ∞ −7

The answer is  ∞======if you are looking for    then imagine putting in a number that is slightly smaller than -7. let's say -7.0001. (the numerator is approximately -7, so put -7 in numerator.)    a number divided by a really really small number results in a huge number. since the result is positive, it is positive infinity.    the answer is ∞. it's really a vertical asymptote at x=-7; it will go up to infinity to the left.

Okay so n is going to represent our first number. since the second number of five times greater than n, the second number will be represented as 5n. for us to figure out the two  numbers we need to have  the value of n first. this is going to be done by adding the two numbers together, n and 5n. it can be simplified as 6n, which the problem states is equal to 72. divide 72 by 6n and you can solve for n.  n+5n=726n=72n=(72/6)n=12  now that we know the value of n, we have to multiply 5 times 12 which equals 60. so our two numbers/integers are 12 and 60

Ithink it's the trapezoid