Qand r are not mutually exclusive events. if p(q)=5/8 and p(r)=1/8 and p(q and r)=1/32,find p(q or r)

The solution for this problem is just adding and subtracting fractions. We all know how to add and subtract function because our teacher since high school teach us how to. P(Q or R) = P(Q) + P(R) - P(Q and R) = 5/8 + 1/8 - 1/32 = 23/32

The answer to this question is 23/32.

Given that the events are not mutually exclusive the union of the probability of the events is calculated through the equation,

 P(Q or R) = P(Q) + P(R) - P(Q and R)

Substituting the known values,

P(Q or R) = 5/8 + 1/8 - 1/32

Simplifying,
 
 P(Q or R) = 23/32

The answer to this item is 23/32. 

B.-2,3 because it is touch the -3 i think that the answer

1. isolate the variable, in this case, d. subtract 35.5 on both sides of the equation.2. 52 subtracted by 35.5 is 16.53. therefore your answer would be d= 16.5this is the basics of pre algebra, isolating variable through adding, subtracting, multiplying, and dividing, if you have any other questions to ask just comment!