The sum of two numbers is 200 and the two numbers are in a ratio of 4: 6 find the larger number

X = 1st number
y = 2nd number

x + y = 200
x : y = 4 : 6

ok! let's substitute numbers!

4 * 10 : 6 * 10

40 : 60

40 + 60 = 200

100 ≠ 200

Too small!

That is exactly two times smaller than 200 so let's try 2 times greater than multiplying by 10

4 * 20 : 6 * 20
80 : 120

80 + 120 = 200

200 = 200

Now it says to find the larger number. Which is y.

x :y = 4 : 6 = 80 : 120

so, y is 120

y = 120

Answer : y = 120. The larger number is 120.