![8^{-\frac{2}{3}}=\\ \left(\frac{1}{8}\right)^{\frac{2}{3}}=\\ \sqrt[3]{\left(\frac{1}{8}\right)^2}=\\ \sqrt[3]{\frac{1}{64}}=\\ \frac{1}{4}](/tpl/images/0215/8900/bac2a.png)
Simplify 8 -2/3 (leave as fraction)
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